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RPSC ME Lecturer 2014: Official Paper

Option 1 : Change in BM over a small length [dM] = Area of SF diagram under that length [Vdx]

ST 1: General Knowledge

5966

20 Questions
20 Marks
20 Mins

__Concept:__

Slope of shear force diagram = Load intensity at that section

\(\frac{{\delta V_x}}{{\delta x}} = - w\)

Slope of bending moment diagram = Shear force at that section

\(\frac{{\delta M_x}}{{\delta x}} = V_x\)

\(w = - \frac{{\delta V_x}}{{\delta x}} = \frac{{{\delta ^2}M_x}}{{\delta {x^2}}}\)

\(V_x = - \smallint wdx;M_x = \smallint V_xdx\)

**Change in BM over a small length [dM] = Area of SF diagram under that length [Vdx]**

If w is n degree curve, V will be (n + 1) degree curve and M will be (n + 2) degree curve.

In case of uniformly distributed load, w is uniform, V is linear, and M is of second order parabola.